(x^2-9)(2x-5)=0

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Solution for (x^2-9)(2x-5)=0 equation: 


Simplifying
(x2 + -9)(2x + -5) = 0

Reorder the terms:
(-9 + x2)(2x + -5) = 0

Reorder the terms:
(-9 + x2)(-5 + 2x) = 0

Multiply (-9 + x2) * (-5 + 2x)
(-9(-5 + 2x) + x2(-5 + 2x)) = 0
((-5 * -9 + 2x * -9) + x2(-5 + 2x)) = 0
((45 + -18x) + x2(-5 + 2x)) = 0
(45 + -18x + (-5 * x2 + 2x * x2)) = 0
(45 + -18x + (-5x2 + 2x3)) = 0
(45 + -18x + -5x2 + 2x3) = 0

Solving
45 + -18x + -5x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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